Check the picture below
use the far-arc near-arc equation
bear in mind, your far-arc and near-arc are both in y-terms, so, the angle will be in y-terms as well
The diameter of the semicircle is 16 feet.
He calculates that he needs to buy abut 25.12 feet of fencing.
To find amount of fencing we find the circumference of semicircle
Circumference of semicircle = 
Where d is the diameter of the circle
d= 16 given and value of pi is 3.14
Circumference of semicircle = 
=25.12 + 16 = 41.12 feet
Scott's calculation was wrong because he forgot to add the diameter d
Circumference of circle is half way of circle plus the diameter of circle.
Correct amount of fencing = 41.12 feet
The answer is 858.55 because A=145(5+25)a2
Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).
