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andrew-mc [135]
2 years ago
8

Describe the likelihood of an event as impossible, unlikely, equally likely, likely or certain. 21) There is a 0% chance of pick

ing a 13 in a deck of cards. _________________ 22) There is a 50% chance of picking a red card in a deck of cards. _______________ 23) There is an 80% chance of snow tomorrow. _________________ 24) There is a 20% chance of rain tomorrow. _________________
Mathematics
1 answer:
Arturiano [62]2 years ago
7 0

Answer:

21) There is a 0% chance of picking a 13 in a deck of cards. <u>Impossible.</u>

If there is a 0% chance that something will happen then it is impossible.

22) There is a 50% chance of picking a red card in a deck of cards.<u> Equally likely.</u>

If there is a 50% chance that something will happen, it is equally likely that it will happen.

23) There is an 80% chance of snow tomorrow. <u>Likely or certain.</u>

If there is an 80% chance of something happening, it means that the chances of that thing happening good and the event is likely to occur.

24) There is a 20% chance of rain tomorrow. <u>Unlikely.</u>

A low chance of 20% means that something is unlikely to occur.

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7 0
3 years ago
The sum of two numbers is 12. The first number, x, is twice the second number, y. Which system of equations could be used to fin
Firdavs [7]

Answer:

D) x+y=12, x=2y

Step-by-step explanation:

We know that x+y=12 and x=2y given the word problem, so D is correct.

3 0
2 years ago
Read 2 more answers
Three businesswomen are trying to convene in Northwest Arkansas for a business meeting. The first (Woman 1) is arriving on a fli
boyakko [2]

Answer:

a) The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.967

d) Expected value of X = E(X) = 2.65

e) Standard deviation = 0.545

Step-by-step explanation:

The probability that the woman coming from Atlanta arrives on time = P(A) = 0.90

The probability that the woman coming from Atlanta DOES NOT arrive on time = P(A') = 1 - 0.90 = 0.10

The probability that the woman coming from Dallas arrives on time = P(B) = 0.95

The probability that the woman coming from Dallas DOES NOT arrive on time = P(B') = 1 - 0.95 = 0.05

The probability that the woman coming from Chicago arrives on time = P(C) = 0.80

The probability that the woman coming from Chicago DOES NOT arrive on time = P(C') = 1 - 0.80 = 0.20

Since X is the random variable that represents how many women arrive on time,

To evaluate the probability function, we will first obtain the probability that the number of women that arrive in time = 0, 1, 2, and 3.

First probability; that no woman arrives on time. X = 0

P(X=0) = P(A') × P(B') × P(C')

= 0.10 × 0.05 × 0.20

P(X=0) = 0.001

Second probability; that only one of the women arrive on time. X = 1

P(X=1) = [P(A) × P(B') × P(C')] + [P(A') × P(B) × P(C')] + [P(A') × P(B') × P(C)]

= [0.90 × 0.05 × 0.20] + [0.10 × 0.95 × 0.20] + [0.10 × 0.05 × 0.80]

= 0.009 + 0.019 + 0.004

P(X=1) = 0.032

Third probability; that only two women arrive on time. X = 2

P(X=2) = [P(A) × P(B) × P(C')] + [P(A) × P(B') × P(C)] + [P(A') × P(B) × P(C)]

= [0.90 × 0.95 × 0.20] + [0.90 × 0.05 × 0.80] + [0.10 × 0.95 × 0.80]

= 0.171 + 0.036 + 0.076

P(X=2) = 0.283

Fourth probability; that all 3 women arrive on time. X = 3

P(X=3) = P(A) × P(B) × P(C)

= 0.90 × 0.95 × 0.8

P(X=3) = 0.684

The probability mass function of X is then presented in the table below.

X | probability P(X=x) or p

0 | 0.001

1 | 0.032

2 | 0.283

3 | 0.684

b) The cumulative distribution function of X

Cdf = Σ pdf = P(X=0) + P(X=1) + P(X=2) + P(X=3)

= 0.001 + 0.032 + 0.283 + 0.684 = 1.000

c) The probability that at least two businesswomen arrive on time

P(X ≥ 2) = P(X=2) + P(X=3) = 0.283 + 0.684 = 0.967

d) Expected value of X

Expected value is given as

E(X) = Σ xᵢpᵢ

E(X) = (0)(0.001) + (1)(0.032) + (2)(0.283) + (3)(0.684) = 0 + 0.032 + 0.566 + 2.052 = 2.65

e) What is the standard deviation of X?

Standard deviation = √(variance)

Variance = Var(X) = Σx²p − μ²

μ = E(X) = 2.65

Σx²p = (0²)(0.001) + (1²)(0.032) + (2²)(0.283) + (3²)(0.684)

= (0)(0.001) + (1)(0.032) + (4)(0.283) + (9)(0.684)

= 0 + 0.032 + 1.132 + 6.156

= 7.32

Variance = Var(X) = 7.32 - 2.65² = 7.32 - 7.0225

Var(X) = 0.2975

Standard deviation = √(variance) = √0.2975

Standard deviation = 0.545

Hope this Helps!!!

8 0
3 years ago
3/4 is added to x, the result is 9/8 . What is the value of x? Enter your answer in the box as a fraction in simplest form.
timofeeve [1]

375/1000 is the answer for u



3 0
3 years ago
Find the value of each factional expression <br><br> 4! <br><br> A 3 <br> B 6<br> C 12<br> D 24
Crank

Answer:

D.

24

Step-by-step explanation:

good luck have a nice day

8 0
3 years ago
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