Answer:
1. A
2. B
3. D
Step-by-step explanation:
Use PEMDAS to solve all
1.
8^2 - 6*2
8*8 - 6*2
64 - 12 = 52
2.
4^2 * 3 + 4 * 2
4 * 4 * 3 + 4 * 2
16 * 3 + 8
48 + 8 = 56
3.
9^2 - 2(5+3)
9 * 9 - 2(8)
81 - 16 =65
<em>Greetings from Brasil...</em>
According to the statement of the question, we can assemble the following system of equation:
X · Y = - 2 i
X + Y = 7 ii
isolating X from i and replacing in ii:
X · Y = - 2
X = - 2/Y
X + Y = 7
(- 2/Y) + Y = 7 <em>multiplying everything by Y</em>
(- 2Y/Y) + Y·Y = 7·Y
- 2 + Y² = 7X <em> rearranging everything</em>
Y² - 7X - 2 = 0 <em>2nd degree equation</em>
Δ = b² - 4·a·c
Δ = (- 7)² - 4·1·(- 2)
Δ = 49 + 8
Δ = 57
X = (- b ± √Δ)/2a
X' = (- (- 7) ± √57)/2·1
X' = (7 + √57)/2
X' = (7 - √57)/2
So, the numbers are:
<h2>
(7 + √57)/2</h2>
and
<h2>
(7 - √57)/2</h2>
The statement is false, as the system can have no solutions or infinite solutions.
<h3>
Is the statement true or false?</h3>
The statement says that a system of linear equations with 3 variables and 3 equations has one solution.
If the variables are x, y, and z, then the system can be written as:
Now, the statement is clearly false. Suppose that we have:
Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.
Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
total pay for his work is $1704
Step-by-step explanation:
given data
Zenin earns = $142 per shift
total shifty = 12
to find out
What would his pay for 12 shift
solution
we have given per shift charge and total shift
so
total pay for his work = total shift × per shift charge ................1
put here value
total pay for his work = 12 × $142
total pay for his work = $1704
Answer:
196: 9.8
20: 1
x= 9.8 meters in 1 second
Step-by-step explanation:
This can be determined by following writing equal ratios that represent a word problem. Then, the denominator must be divided from the numerator to get the unit rate/ meters per second.
