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sleet_krkn [62]
3 years ago
14

A deli sandwich consists of one type of bread, one type of meat, and one type of sauce. The deli offers wheat, rye, and white br

ead; ham, turkey, roast beef, and tuna; ranch and southwest chipotle sauce. Javier is allergic to rye bread, tuna, and southwest chipotle sauce. He tells the server to assemble a random deli sandwich. What is the probability that Javier will suffer an allergic reaction?
Mathematics
2 answers:
USPshnik [31]3 years ago
5 0
1/3 because there is 3 types of each item, and he is allergic to one of the three. so, there is a 1/3 chance that one of those ingredients will be chosen on the sandwich
Archy [21]3 years ago
3 0
It would be 1/3 because there are three ingredients. Therefore, if he is allergic to one of everything in each category, there are 3/10 things he is allergic to.
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Answer:

P.7500.00

Step-by-step explanation:

We are told that:

The ratio of Val's savings to Dan is 2:3 at first.

Now, Dan spent P3000.00 and Val's saving became 1⅓ more of that Dan's remaining savings.

Let's say the total amount of savings they had at first was x.

Thus;

Val had: 2x/5

Dan had: 3x/5

Now, Dan spent P3000.00.

So amount Dan has left = (3x/5) - 3000

We are told Val's savings is now 1⅓ = 4/3 times that of Dan's remaining savings

Thus; 2x/5 = (4/3)((3x/5) - 3000)

2x/5 = 12x/15 - 4000

Multiply through by 15 to get;

6x = 12x - (3000 × 15)

6x = 12x - 45000

Rearranging, we have;

12x - 6x = 45000

6x = 45000

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x = P.7500

4 0
3 years ago
What is the answer to 16a5 b3/8ab ?
marishachu [46]

Answer:

When we are dividing exponents, there is this rule:

\frac{a^n}{a^m}=a^{(n-m)}

So, in our case we have this:

\frac{16a^5b^3}{8ab} = \frac{16}{8}a^{(5-1)}b^{(3-1)}=2a^4b^2

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Step-by-step explanation:

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7 0
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If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ
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Answer:

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Step-by-step explanation:

You didn't specify where the point P is so there are two posibilites:

1.

P₁Z is dividing angle OZQ

then:

      m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°

2.

P₂Z is outside angle OZQ

then

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