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Andru [333]
3 years ago
9

How many tablespoon of Vanilla extract do you need for 1 gallon of milk

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
5 0
Answer: 1-3 tablespoons
Explanation: bc
Setler79 [48]3 years ago
3 0
Not enough information
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-2x - 5y = 13 2x - 5y =17
Flura [38]

{-2x-5y=13

<u>{2x-5y=17    </u>(+)

<em />  -2x+2x-5y-5y=13+17

-10y=30     /:(-10)

y=-3

2x-5y=17

2x-5*(-3)=17

2x+15=17

2x=2

x=1

<em>Solution: (1; -3)</em>       

6 0
3 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Which inequality is true?
Vladimir79 [104]

Answer:

C) 3pi>9

Step-by-step explanation:

5 0
3 years ago
A textbook has 428 pages numbered in order starting with 1. You flip
BartSMP [9]

Here's link to the answer:

linkcutter.ga/gyko

8 0
3 years ago
Read 2 more answers
2) Which rectangle if translated 6 units right and 16 units down and the rotated 90° clockwise about the point (4, -11) will res
Veronika [31]

Answer:

the answer should be c

Step-by-step explanation:

5 0
3 years ago
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