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3 years ago

Trend lines

Mathematics

1 answer:

Mashcka [7]3 years ago

6 0

Answer: the slope is 3 and the intercept is 0.

Step-by-step explanation:The trend line for the bivariate data shown in the scatter plot has the equation Y=3x

To determine the slope for a straight line (y=a*x+b)we take the two points that are shown and apply the following equation:

To determine the intercept we put the slope which we calculated into the equation for the point (2,6) and clear for b

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Select the correct answer.

makvit [3.9K]

Answer:

Step-by-step explanation:

y = 52° ( Opposite Angles )

y + 2x = 180° ( Interior Angles )

$y + 2x = {180}^{o} \\ {52}^{o} + 2x = {180}^{o} \\ 2x = {180}^{o} - {52}^{o} \\ 2x = {128}^{o} \\ x = \frac{ {128}^{o} }{2} \\ x = {64}^{o} \\$

3 0

3 years ago

Last year, Lien earned $1,600 more than her husband. Together they earned $51,000. How much did each of them earn?

jok3333 [9.3K]

Answer:

Lien: $26300 Her husband: $24700

Step-by-step explanation:

x+(x+1600)=51000

2x+1600=51000

2x=49400

x=24700

Her husband earned 24700

24700+1600=26300

Lien earned 26300

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3 years ago

Which characteristics best describe an acute isosceles triangle?

Paladinen [302]

Isocoleese means that 2 sides and hence 2 angles are same measure
acute means that all 3 angles are less than 90 degrees

We can rule out choice I since acut means less than 90

II is a possibility, but it doesn't best describe it

III. that is true, but it doesn't include the isocileese part

IV. that is true, but doesn't include the acute part

not sure, either III or IV

4 0

3 years ago

Read 2 more answers

Using sum or difference formulas, find the exact value of sin(165∘)

Nikitich [7]

$\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\
-------------------------------\\\\$

$\bf sin(165^o)\implies sin(120^o+45^o)
\\\\\\
sin(120^o)cos(45^o)~+~cos(120^o)sin(45^o)\implies \cfrac{\sqrt{3}}{2}\cdot \cfrac{\sqrt{2}}{2}~+~\cfrac{-1}{2}\cdot \cfrac{\sqrt{2}}{2}
\\\\\\
\cfrac{\sqrt{6}}{4}~-~\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}$

6 0

3 years ago

SOMEONE HELP IM LITTRALY GONNA CRY MY DUDES PLEASE

forsale [732]

Answer:

Step-by-step explanation:

ewqrui

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3 years ago