m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
Answer:
See picture
Step-by-step explanation:
The rule is ...
![x^{m/n}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
The index of the surd becomes the denominator of the exponents inside.
Answer:
please provide the diagram
Answer:
C.) 87
Step-by-step explanation:
if you look at it from the other side, its counting down from 91 from the left.