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mina [271]
3 years ago
8

Find the perimeter of the figure to the nearest hundredth. Sorry to ask ANOTHER question on this stuff but I'm doing an assignme

nt and I don't get it-

Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

I did my best, but it has been a while. I really hope that this helps

Step-by-step explanation:

so you can find the perimeter of a circle

-----The perimeter of a circle is π × d where d is the diameter so half of that is 1/2 π × d. But If you are going to walk around a semicircle, you need to go halfway around the circle and then across a diagonal to get back to where you started, so the perimeter is 1/2 π × d + d.

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Find a ·<br> b. |a| = 80, |b| = 50, the angle between a and b is 3π/4.
mart [117]

Answer:

a\cdot b=-2000\sqrt{2}

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product  a · b.

The formula of dot product is

a\cdot b=|a||b|\cos \theta

where, θ is the angle between a and b.

Substitute the given values in the above formula.

a\cdot b=(80)(50)\cos (\frac{3\pi}{4})

a\cdot b=4000\cos (\pi-\frac{\pi}{4})

a\cdot b=-4000\cos (\frac{\pi}{4})           [\because \cos (\pi-\theta)=-\cos \theta]

a\cdot b=-4000\frac{1}{\sqrt{2}}

a\cdot b=-\frac{4000}{\sqrt{2}}

Rationalize the above equation.

a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}

a\cdot b=-\frac{4000\sqrt{2}}{2}

a\cdot b=-2000\sqrt{2}

Therefore, the value of a · b is a\cdot b=-2000\sqrt{2}.

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3 years ago
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<u>21.1</u>

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please choose me as brainly

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