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Marta_Voda [28]
3 years ago
11

A jet travels 560 miles in 5 hours. At this rate, how far could the jet fly in 9 hours? What is the rate of the speed of the jet

?
Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

In order to figure out how far a plane could fly in 9 hours, we have to use unit rate.

(Unit rate is the value you get in one unit, such as Miles Per Hour, or Dollars Per Pound)

In order to figure out \frac{miles}{1 hour}, we have to simplify the rate we already have.

The given rate is \frac{560}{5}, and in order to get the unit rate, we simply have to simplify the fraction by dividing both sides by 5:

\frac{560/5}{5/5} = \frac{112}{1}

Now we know that the unit rate is \frac{112 miles}{1 hour}

Now, let's use an example.

If a car was going 60 miles per hour for 3 hours, how far would it go? In this case, you'd simply have to multiply 60 and 3 together. The car would travel 180 miles.

Back to the question.

If the jet travels \frac{112 miles}{1 hour}, how far would it fly in 9 hours?

If you looked at the example, then you already know that you simply have to multiply 112 and 9!

\frac{112 miles}{1 hour} * 9 = 1008

<u>The jet can fly 1008 miles in 9 hours, and the unit rate is \frac{112 miles}{1 hour}.</u>

Good luck! If you have any questions, just ask! :))

leonid [27]3 years ago
3 0

Answer:

1,008

Step-by-step explanation:

560/5 * x/9

x=1,008

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Drina wrote the system of linear equations below.
zalisa [80]

Answer:

Option c, A square matrix

Step-by-step explanation:

Given system of linear equations are

3x-2y=-2\hfill(1)

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Now to find the type of matrix can be formed by using this system

of equations

From the given system of linear equations we can form a matrix

Let A be a matrix

A matrix can be written by

A=co-efficient of x of 1st linear equation    co-efficient of y of 1st linear equation   constant of 1st terms linear equation

co-efficient of x of 2st linear equation   co-efficient of y of 2st linear equation  constant of 2st terms linear equation

co-efficient of x of 3st linear equation   co-efficient of y of 3st linear equation    constant of 3st terms linear equation           3\times 3

which is a 3\times 3 matrix.

Therefore A can be written as

A= \left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3

Matrix "A" is a 3\times3 matrix so that it has 3 rows and 3 columns

A square matrix has equal rows and equal columns

Since matrix "A" has equal rows and columns Therefore it must be a square matrix

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MaRussiya [10]

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

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