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IRISSAK [1]
2 years ago
9

Which of the following statements is NOT true? All whole numbers are rational numbers. All whole numbers are rational numbers. A

ll counting numbers are whole numbers. All counting numbers are whole numbers. All integers are whole numbers. All integers are whole numbers. All integers are rational numbers
Mathematics
1 answer:
san4es73 [151]2 years ago
8 0

Answer: All counting numbers

Step-by-step explanation:

You could use decimals and fractions technically

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Solve the following system by graphing and identify the point of intersection -5x+2y=-4 2x-y=2
FrozenT [24]

Answer: Point of intersection (0, -2)

Step-by-step explanation:

8 0
1 year ago
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P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
2 years ago
the sum of two numbers is 67 if three times the smaller number is subtracted by the larger the result is 7, find two numbers
just olya [345]
Um I think it's 3x7x4=81 or like this 40+20+7=67.
3 0
3 years ago
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What is e+f/g in distributive property​
enot [183]

Answer:

e/g+f/g

Step-by-step explanation:

(e+f)/g  can be split up. e/g+f/g is equal to (e+f)/g so your answer is e/g +f/g

7 0
2 years ago
Slope of 2y = -x + 10
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The slope would be -1 because of the x
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