Answer:
Natalie bought 500 apples at $0.40 each, then she pays $0.40 500 times, this means that the total cost of the 500 apples is:
Cost = 500*$0.40 = $200
Now she threw away n apples from the 500 apples, then the number of apples that she has now is:
apples = 500 - n
And she sells the remaining apples for $0.70 each.
a) The amount that she gets by selling the apples is:
Revenue = (500 - n)*$0.70
b) We know that she did not make a loss, then the revenue must be larger than the cost, this means that:
cost ≤ revenue
$200 ≤ (500 - n)*$0.70
c) We need to solve the inequality for n.
$200 ≤ (500 - n)*$0.70
$200/$0.70 ≤ (500 - n)
285.7 ≤ 500 - n
n + 285.7 ≤ 500
n ≤ 500 - 285.7
n ≤ 214.3
Then the maximum value of n must be equal or smaller than 214.3
And n is a whole number, then we can conclude that the maximum number of rotten apples can be 214.
Hello from MrBillDoesMath!
Answer: 1/12
Discussion:
We solve 5/12 + x = 1/2 for x. Begin by subtracting 5/12 from each side
5/12 - 5/12 + x = 1/2 - 5/12
0 +x = 6/12 - 5/12 (as 1/2 = 6/12)
So x = 1/12
Regards, MrB
Answer:
1lb
Step-by-step explanation:
He bought two lbs of ground beef and used a pound to make hamburgers therefore he has a pound left over.
So.... there are a total of 57 toys, which the new and favorites ones are not going to be sold.
The equation would ultimately go into 57 - (15+9+2), which would equal to 31. Ultimately, he sells 31 toys and have 26 left over.
in short, subtracting 57 with the sum of 15+9+2 would equal to 31 toys which means that he sells the 31 toys.
