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solmaris [256]
3 years ago
9

Brissa's desk is 3 feet long. About how long is it in meters? use 1 foot = 0.305 meter

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0
Answer:
0.914
Correct me if I’m wrong plz
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A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be desc
g100num [7]

Answer:

y - Q = -5/2(x - P)

Step-by-step explanation:

The equation of a line in point slope form is expressed as y - y0 = m(x-x0)

(x0, y0) is the point

m is the slope

Given the equation

y = 2/5x− 4.

Slope m  = 2/5

Slope of the perpendicular line = -1/(2/5) = -5/2

Point;

x0 = P

y0 = Q

Substitute into the formula;

y - y0 = m(x-x0)

y - Q = -5/2(x - P)

This gives the required equation

5 0
2 years ago
If and , find .<br><br> A. <br> B. <br> C. <br> D.
trapecia [35]
Answer: option D. 2x^2 + (3/2)x  - 5

Explanation:

1) polynomials given:

 f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3

2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

3) x/2  - 2 + 2x^2 + x - 3

4) Combine like terms:

a) terms with x^2: you only have 2x^2, so it is not combined with other term.

b) terms with x: x/2 + x

that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x

c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.


4 0
3 years ago
URGENT PLEASE HELP
OleMash [197]

Answer:

6.32

Step-by-step explanation:

6^2 - 2^2

✓40

=6.32455532

2d.p = 6.32

3 0
2 years ago
B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}

Then by the chain rule,

\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}

So we have

g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}

and we can simplify this by factoring out 18(36-x^2)^{-3/2} to end up with

g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}

5 0
2 years ago
7x+1=8x+3<br><br> Please help I did it but it said my answer was wrong
sweet-ann [11.9K]

I did some math and i got this

x = -2

8 0
2 years ago
Read 2 more answers
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