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Orlov [11]
3 years ago
10

Solve the system.... 2y+8x+58 and y-5x=11

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

x=2, y=21

Step-by-step explanation:

there are two methods: substiution and elimation. I will be doing subtistution in this soultion:

first isolate y in either equation, it would be easier to do it in the second one.

y= 11+5x

Then, subtitute that into the first equation

2(11+5x)+8x=58 (it says 2y+8x+58 but I assume you mean 2y+8x=58?)

22+10x+8x=58

18x = 36

x=2

substitute that back into y = 11+5x, to get y=11+10 = 21

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Answer:

2(4-x)=26

Step-by-step explanation:

<u><em>1. Plug "-9" into each equation as "x"</em></u>

2(4--9)=26

5(-9)+30=75

5(12--9)=15

3(-9+11)=-16

<u><em>2. Solve each equation</em></u>

2(4--9)=26 ~ 26=26

5(-9)+30=75 ~ -5=75

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7 0
3 years ago
Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is
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Answer:

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Step-by-step explanation:

Has 29 problems

then

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7 0
4 years ago
5 less than the product of 5 and a number y is 22..... (y=?)
Dominik [7]
5 less than the product of 5 and a number y is 22. (5y - 5 = 22)

Let's try to work backwards with this.
I
f we add 5 to 22, we get 27. (5y - 5 + 5 = 22 + 5)

27 divided by 5 is 5.4. (5y ÷ 5 = 27 ÷ 5)
 
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Answer:

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Step-by-step explanation:

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