<h2><em>Find the LCD of 1/3 and 1/2.</em></h2><h2><em>The LCD is 6.</em></h2><h2><em>1/3 in 6ths is 2/6.</em></h2><h2><em>1/2 in 6ths is 3/6.</em></h2><h2><em>2/6 + 3/6 = 5/6.</em></h2><h2><em>1/3 + 1/2 = 5/6.</em></h2><h2><em>Hope this helps and have a nice day.</em></h2>
Answer:
Step-by-step explanation:
<em>hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em> </em><em>more</em><em> </em>
<em>have</em><em> </em><em>a</em><em> </em><em>great</em><em> </em><em>day</em><em>.</em><em>.</em>
Answer:
the answer is 100 I promise
Answer:
The revenue depends on the number of people n that purchases tickets, knowing that each ticket costs $30.00, the total revenue will be:
f(n) = $30.00*n
Now, we also know that the stadium is capable of seating a maximum of m fans, so the maximum possible value for n is m.
Now, for the function f(n), we have that:
The domain is the set of the possible values of n
The range is the set of the possible values of f(n).
We want to find the domain.
First, the minimum possible value of n is 0, the case where nobody purchases a ticket.
The maximum possible value of n is m, this is the case where the stadium is full.
Then the domain will be:
D= {n,m ∈ Z, 0 ≤ n ≤ m}
Where we imposed that n must be an integer number because n represents a whole quantity.
