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djyliett [7]
3 years ago
15

The service box is an area on the court that 1 point the person serving must stand in. the ball must land in to be a playable se

rve. the person returning the serve must be standing in before a server can serve ​
Biology
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

Both players on the serving doubles team have the opportunity to serve and score points until they commit a fault *(except for the first service sequence of each new game).

The first serve of each side-out is made from the right-hand court.

If a point is scored, the server switches sides and the server initiates the next serve from the left-hand court.

As subsequent points are scored, the server continues switching back and forth until a fault is committed and the first server loses the serve.

When the first server loses the serve the partner then serves from their correct side of the court (except for the first service sequence of the game*).

The second server continues serving until his team commits a fault and loses the serve to the opposing team.

Once the service goes to the opposition (at side out), the first serve is from the right-hand court and both players on that team have the opportunity to serve and score points until their team commits two faults.

In singles the server serves from the right-hand court when his or her score is even and from the left when the score is odd.

Explanation:

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directional selection

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Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

4 0
3 years ago
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