67.04,67.039,67.39,68.994
X=15 and y=6
15-6=9
15+2(6)=27
2(6)=12
Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
2370 / (2/5) = x / 1...2370 to 2/5 = x to 1
cross multiply
(2/5)(x) = (2370)(1)
2/5x = 2370
x = 2370 * 5/2
x = 11850/2 = 5925 <== their entire goal
Answer:
$32
Step-by-step explanation:
24 divided by 3= 8
8*4=32
