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GREYUIT [131]
3 years ago
11

henry is mixing concrete. to make concrete he needs to mix cement, sand and gravel in the ratio 5 : 4 : 1 by weight. henry needs

to make 110kg of concrete. he has 50kg cement, 55kg of sand and 15kg of gravel. which ingredient is henry short of?
Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

cement by 5 Kg

Step-by-step explanation:

add the parts of the ratio, 5 + 4 + 1 = 10 parts

Divide the quantity of concrete by 10 to find the value of one part of the ratio.

110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus

5 parts = 5 × 11Kg = 55Kg ← cement required

4 parts = 4 × 11Kg = 44Kg  ← sand required

1 part = 11Kg ← gravel required

He requires 55Kg of concrete but only has 50Kg.

He requires 44Kg of sand and has 55Kg

He requires 11Kg of gravel and has 15Kg

Thus he is 5Kg short of cement.

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Answer:

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Step-by-step explanation:

Solve any pre-algebraic equation with inverse operations:

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multiply both sides by -10

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now simplify:

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Answer:

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Step-by-step explanation:

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Ration of side=(1.21x)^(1/2)/(x)^(1/2)=1.1=11/10.

Answered by Gauthmath

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3 years ago
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Answer:

Step-by-step explanation:

Let angles are 2x,3x,5x

So given 2x=50

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Answer:

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