Answer:
BC= 15
if I am right please mark it as brianliest
Parallel is MN and QP and perpendicular is MQ and OP
Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,
And
We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Answer:
One Solution
Step-by-step explanation:
Trust me
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
