Question

Number of Packets

Answer 1

Answer:

13. $D = 18$

14. $S = (x, y + 6)$

Step-by-step explanation:

13.

Given

$M = (-8,2)$

$S = (10,2)$

Required

Determine the distance between M and S

Distance (D) is calculated using:

$D = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$

Where

$(x_1,y_1) = (-8,2)$

$(x_2,y_2) = (10,2)$

$D = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$

$D = \sqrt{(10 - (-8))^2 + (2 - 2)^2}$

$D = \sqrt{(10 +8)^2 + 0^2}$

$D = \sqrt{18^2 + 0}$

$D = \sqrt{18^2}$

$D = 18$

Hence, the distance between M and S is 18 units

14.

The coordinate of S and P are not given,

So, I'll just use (x,y) for P

i.e.

$P=(x,y)$

Required

Determine the coordinates of S

If S is 6 units above P, then the coordinates of S is

$S = (x, y + 6)$

i.e. we add the units to the y coordinate of P.