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Artemon [7]
3 years ago
5

What are the y-coordinates for the solution to the system of equations:{y−x2+9x−6=0

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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if each dimension of a unit cube is increased by 1. what is the ratio between the surface area of the new cube to that of the or
nexus9112 [7]

Answer:

4:1 or 4/1

Step-by-step explanation:

Original surface area: Each side is 1 * 1 = 1 and there are 6 sides, so 1 * 6 = 6.

New surface area: Each side is 2*2 = 4, and there are 6 sides, so 4 * 6 = 24

The ratio would be 24:6, or 4:1. As a fraction, this would be 4/1

4 0
3 years ago
Read 2 more answers
Ronald started solving the equation −2(2x−4)+3=6x+1.<br><br> Which is a correct next step?
Snowcat [4.5K]

Answer:

distribute bud

Step-by-step explanation:

distribute throught the parethesis first

8 0
3 years ago
Read 2 more answers
−4.2(−2.8+4.5)​ I think I know what the answer is but I just want to be 100% sure. Please solve this and tell me your answer. I
Talja [164]

Answer:

-7.14

Step-by-step explanation:

Evaluate

−4.2(−2.8 + 4.5)​

Open parenthesis

(-4.2 * -2.8) + (-4.2 * 4.5)

= (11.76) + (- 18.9)

= 11.76 - 18.9

= -7.14

NOTE:

Negative (-) × negative (-) = positive (+)

Positive (+) × positive (+) = positive (+)

Negative (-) × positive (+) = negative (-)

Positive (+) × negative (-) = negative (-)

7 0
3 years ago
How many 1/3 cups of ice cream can you make from 1/7 cup
OlgaM077 [116]
Well first you have to make the denominators equal by finding a common denominator. in this case 21, but whatever you do to the bottom you do to the top. so 1/3 times 7/7 equals 7/21 and 1/7 times 3/3 equals 3/21.
 
so how many 7/21 cups of ice cream can you make from 3/21 i think  about none but remember i could be wrong
8 0
3 years ago
Evaluate the limit of tan 4x/ 4tan3x​
Brut [27]

Answer:

  1/3

Step-by-step explanation:

The ratio is undefined at x=0, so we presume that's where we're interested in the limit. Both numerator and denominator are zero at x=0, so L'Hôpital's rule applies. According to that rule, we replace numerator and denominator with their respective derivatives.

  \displaystyle\lim\limits_{x\to 0}\dfrac{\tan{(4x)}}{4\tan{(3x)}}=\lim\limits_{x\to 0}\dfrac{\tan'{(4x)}}{4\tan'{(3x)}}=\lim\limits_{x\to 0}\dfrac{4\sec{(4x)^2}}{12\sec{(3x)^2}}=\dfrac{4}{12}\\\\\boxed{\lim\limits_{x\to 0}\dfrac{\tan{(4x)}}{4\tan{(3x)}}=\dfrac{1}{3}}

6 0
3 years ago
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