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sergejj [24]
3 years ago
6

PLEASE, I NEED HELP WITH THIS QUESTION!!!!

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

7 , 5 , 9

Step-by-step explanation:

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Area for rectangle in the coordinate plane. IXL Geometry help pls !
Sidana [21]

Answer:

Step-by-step explanation:

The co-ordinates of the rectangle are:

A (8, 6)

B (-4, -10)

C (-8, -7)

D (4, 9)

The Area of Rectangle is Given by: <em>length x breadth </em>= AB x BC

Lengths of AB and BC can be found by distance formula

<em>length</em>(AB) = \sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2}} = \sqrt{(-4-8)^{2} + (-10-6)^{2}} = 20

Similarly,

<em>length</em>(BC) = 5

Area of Rectangle = AB x BC = 20 x 5 = 100 square units

5 0
3 years ago
A 16-inch cheese pizza at Fine Dough Pizza costs $10.00 and each additional topping is $1.50. The same size pizza at Johnson's P
natta225 [31]
1 topping on the 8$ they will cost the same but the 10$ cost more with aditional toppings unless both pizzas have 5 toppings then the 8$ would cost 50 cents more
4 0
3 years ago
Alicia has been putting her money from work into her savings account. The equation f(x)=13x+100 can be used to represent the inc
labwork [276]

Answer:

f(18)=334

Step-by-step explanation:

  • f(x)=13x+100
  • f(18) = 13(18)+100
  • f(18)=234+100
  • f(18)=334
3 0
3 years ago
Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

c = 0

y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

8 0
3 years ago
Which of the
kondor19780726 [428]

The pic is attached.

7 0
3 years ago
Read 2 more answers
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