So hmm notice the picture below
you have the center, and a point on the circle... all you need is the radius
then use that radius in the circle's equation
Answer: 0
Step-by-step explanation:
h ( t ) = − 2 t ^2 + 10 t
h = height of ball above the ground
t = time, seconds after ball was kicked
Height of ball at the time it is kicked?
At the time ball is kicked, time (t) = 0
Therefore,
h ( t ) = − 2 t ^2 + 10 t
h( 0) = - 2(0)^2 + 10(0)
h = 0 + 0
h = 0
The ball was the on the grounf at the time it was kicked.
Remark
I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.
So DEB + DCB = 180o
DEB = 180 - 87
DEB = 93o
Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.
Answer:
i think it is A, C, OR B, **For the first equation**
Step-by-step explanation:
SRRY IF WRONG!
B. no the answer isn't reasonable, it should be about 3 quarts.
