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3 years ago

Please help answer questions

Mathematics

1 answer:

Elena-2011 [213]3 years ago

6 0

Answer:

Step-by-step explanation:

For a x= 21

b) x= -20

c) x=5

D)x<5

e)x>8 you have to put w\variables on one side and numbber on the other side in algebra hope it helps!

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What value does the 2 in the number 0.826?

Deffense [45]

Answer:

.02

Step-by-step explanation:

2 is in "Hundredths' place in .826

So, the number is multiplied with 1/100 or .01

=> 2 x 1/100

=> 2/100

=> .02

=> 2 x .01

=> .02

The value of 2 in .826 is .02

6 0

3 years ago

What’s the answer?? need help

Butoxors [25]

Answer:

option A.

$a^{9}b^{6}$

Step-by-step explanation:

To solve this, we need to use the following exponent rules:

Quotient rule: (a^n)/(a^m) = a^(n-m)

Power rule: (a^n)^m = a^nm

Power of a product rule: (ab)^n = (a^n)(b^n)

Then, we have the following expressions:

$[\frac{a^{-8}b}{a^{-5} b^{3}}}]^{-3}=[a^{-8+5}b^{1-3}}}]^{-3}=[a^{-3}b^{-2}]^{-3} =a^{9}b^{6}$

So the correct result is option A.

$a^{9}b^{6}$

7 0

3 years ago

Lines 1 and 2 are parallel. Find the measure of x.

Vesnalui [34]

Answer:

Step-by-step explanation:

180-63 is 117

a line is 180 all together so therefore if we subtract the 63, we get the answer we want

7 0

3 years ago

Read 2 more answers

Jose put$1500 into a savings account. He earns 3% interest every year. How much simple interest will he earn at the end of 3 yea

ehidna [41]

Answer

$3142

Step-by-step explanation:

8 0

4 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0

4 years ago