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gizmo_the_mogwai [7]
3 years ago
15

What value does the 2 in the number 0.826?

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

.02

Step-by-step explanation:

2 is in "Hundredths' place in .826

So, the number is multiplied with 1/100 or .01

=> 2 x 1/100

=> 2/100

=> .02

=> 2 x .01

=> .02

The value of 2 in .826 is .02

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I need help solving these problems​
Delicious77 [7]

QUESTION 1

4 {p}^{2}  =  2 \times 2\times  {p} \times p

QUESTION 2

39 {b}^{3}  {c}^{2}  = 3 \times 13 \times  {b} \times b \times b\times  {c} \times c

QUESTION 3

100 {x}^{3} y {z}^{2}  =  {2} \times 2 \times  {5} \times 5  \times  {x} \times x \times x\times y \times  {z} \times z

QUESTION 4

66 {d}^{4}  = 2 \times 3 \times 11 \times  {d} \times d \times d \times d

QUESTION 5

85 {x}^{2}  {y}^{2}  = 5 \times 17 \times  {x} \times x   \times {y} \times y

QUESTION 6

18xy = 2 \times  {3}^{2}  \times x \times y

36 {y}^{2}  =  {2}^{2} \times  {3}^{2}   \times  {y}^{2}

The greatest common factor is the product of the least powers of the common factors;

GCF=2 \times  {3}^{2}  \times y

GCF=18y

QUESTION 7

25mn =  {5}^{2}  \times m \times n

21m = 3 \times 7 \times m

GCF=m

QUESTION 8

15a = 3 \times 5 \times a

28a {b}^{2}  =  {2}^{2}  \times 7 \times a \times  {b}^{2}

GCF=a

QUESTION 9

24 {d}^{2}  =  {2}^{3}  \times 3 \times  {d}^{2}

30 {c}^{2} d = 2 \times 3 \times 5 \times d

GCF=2 \times 3 \times d

GCF=6d

QUESTION 10

20gh =  {2}^{2}  \times 5 \times g \times h

36 {g}^{2}  {h}^{2}  =  {2}^{2}  \times  {3}^{2}  \times  {g}^{2}  \times  {h}^{2}

GCF= {2}^{2}  \times g \times h

GCF=4gh

QUESTION 11

17 {c}^{3}  {d}^{2}  = 17 \times  {c}^{3}  \times  {d}^{2}

5 {c}^{2}  {d}^{2}  = 5 \times  {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}{d}^{2}

4 0
3 years ago
Share 56 sweets in the ratio 2 : 5.
kherson [118]
Answer is 16:40

Add up the parts of the sweets so 2+5=7.
Then with the total amount (56)/7=8.
8x2= 16
8x5=40
5 0
2 years ago
5.
SVETLANKA909090 [29]
You should try C I’m not sure but try I guess!
4 0
2 years ago
Read 2 more answers
A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op
Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, \dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h

Volume of cone is given by

V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3

By differentiating with respect to time t, we get that

\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}

Now,  the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie \dfrac{dv}{dt}=-4\ in^3

and h = 2 inches deep.

-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0
3 years ago
Can someone help me please
allsm [11]

Answer:

No more than ≥

Not under ≤

No less than ≤

maximum ≥

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Less than or equal to ≤

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4 0
3 years ago
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