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3 years ago

What value does the 2 in the number 0.826?

Mathematics

1 answer:

Deffense [45]3 years ago

6 0

Answer:

.02

Step-by-step explanation:

2 is in "Hundredths' place in .826

So, the number is multiplied with 1/100 or .01

=> 2 x 1/100

=> 2/100

=> .02

=> 2 x .01

=> .02

The value of 2 in .826 is .02

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Step-by-step explanation:

9 X 1 = 9

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Etc.

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3 years ago

If the price of dishwashing detergent increased at the same rate as the CPI from 1970 to 1980, how much did a bottle of dishwash

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Read 2 more answers

A line passes through the point (10,9) and has a slope of 3/2. Write an equation in slope intercept form for this line

Andre45 [30]

Answer:

The equation of line passing through (10,9) and having slope 3/2 is: $y = \frac{3}{2}x-6$

Step-by-step explanation:

The slope intercept form of a line is given by:

$y=mx+b$

We are given

Slope = m = 3/2

Point = (10,9)

Putting the value of the slope in the equation we get

$y = \frac{3}{2}x+b$

b is the y-intercept. To find the y-intercept we have to put the point through which the line passes in the equation.

Putting (10,9) in the equation

$9 = \frac{3}{2}(10) +b\\9 = 15+b\\b = 9-15\\b = -6$

Putting b=-6 in the equation

$y = \frac{3}{2}x-6$

Hence,

The equation of line passing through (10,9) and having slope 3/2 is: $y = \frac{3}{2}x-6$

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3 years ago

Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda

pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

Step-by-step explanation:

Given equation is

$x^2y'' - 9xy+24y=0$

This Euler Cauchy type differential equation.

So, we can let

$y=x^m$

Differentiate with respect to x

$y'= mx^{m-1}$

Again differentiate with respect to x

$y''= m(m-1)x^{m-2}$

Putting the value of y, y' and y'' in the differential equation

$x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0$

$\Rightarrow m(m-1)x^m-9mx^m+24x^m=0$

$\Rightarrow m^2-m-9m+24=0$

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

$y_1(x)=x^4$

and

$y_2(x)=x^6$

First we compute the Wronskian

$W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|$

$= \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|$

=x⁴×6x⁵- x⁶×4x³

=6x⁹-4x⁹

=2x⁹

≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

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3 years ago