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3 years ago

Help I will give all the good stuff to you if you help me!

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

Answer:

I think it is triangle, pentagon, heptagon, decagon

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State what additional information is required in order to know that the triangles are congruent

AleksandrR [38]

17 && 19 are both congruent.

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2 years ago

A square has a diagonal of length 12. Find the length of each side.

White raven [17]

Answer:

Step-by-step explanation:

12÷4=3

Hope this will help you!

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2 years ago

TJ-Maxx offered a 36% discount off the original price of a head board. The amount of the discount is $9. What is the regular pri

jok3333 [9.3K]

The amount if the original cost of the head board is $12.24

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2 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

8 0

3 years ago

Read 2 more answers

Find the value of cos 28°cos 62°– sin 28°sin 62°

Romashka [77]

<h2>Answer:</h2>

cos 28°cos 62°– sin 28°sin 62° = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

cos(A+B) = cosAcosB - sinAsinB -----------------(i)

We can apply such identity to solve the given expression.

Given:

cos 28°cos 62°– sin 28°sin 62°

Comparing the given expression with the right hand side of equation (i), we see that;

A = 28°

B = 62°

∴ Substitute these values into equation (i) to have;

⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°

Solve the left hand side.

⇒ cos(90°) = cos28°cos62° - sin28°sin62°

⇒ 0 = cos28°cos62° - sin28°sin62° (since cos 90° = 0)

Therefore,

cos28°cos62° - sin28°sin62° = 0

8 0

2 years ago