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V125BC [204]
3 years ago
5

Michael runs a distance of 5 1/4 miles in 45 3/4 minutes during a fade. At this rate, what is Michaels average speed in miles pe

r hour?
Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer: Micheal's average Speed =6.885 miles per hour

Step-by-step explanation:

Speed= Distance /time

Given the distance he ran as  = 5 1/4 miles

And Time taken = 45 3/4 minutes

changing to hours becomes

60 mins = 1 hour

45 3/ 4 mins = 45 3/4 mins/ 60mins x 1hour

= 45.75 /60 =  0.7625hours

Therefore Micheal's average Speed= Distance /time

             =5 1/4miles / 0.7625hours = 5.25/ 0.7625

              =6.885 miles per hour

approximately 7 miles/hour.

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Step-by-step explanation:

check attachment for detail explanations

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3 years ago
Please help!!!!<br> I desperately need the correct answer I’ve been trying all day!
zysi [14]

Answer:14708

Step-by-step explanation:Exponential Functions:

y=abxy=ab^x this is not right      not correct

y=ab

x

a=starting value = 13000a=\text{starting value = }13000

a=starting value = 13000

r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025

r=rate = 2.5%=0.025

Exponential Growth:\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025

b=1+r=1+0.025=1.025

Write Exponential Function:

y=13000(1.025)xy=13000(1.025)^x

y=13000(1.025)

x

Put it all together

Plug in time for x:\text{Plug in time for x:}

Plug in time for x:

y=13000(1.025)5y=13000(1.025)^{5}

y=13000(1.025)

5

y=14708.30677y= 14708.30677

y=14708.30677

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y≈14708y\approx 14708

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5 0
3 years ago
Read 2 more answers
Identify the type of sequence shown and select the appropriate response.
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Answer:

the answer is A

Step-by-step explanation:

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3 years ago
6 * 10^8 is how many times as large as 2 * 10^3
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3 years ago
Read 2 more answers
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

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\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

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3 years ago
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