Answer:
x=8
Step-by-step explanation:
10x + 80 < y = 20x
subtract 80 from both sides
10x = 20x - 80
subtract 20 from both sides
-10x = -80
divide both sides by -10
8
Expand f(z) into partial fractions:
Recall that for |z| < 1, we have the power series
Then for |z| > 2, or |1/(z/2)| = |2/z| < 1, we have
So the series expansion of f(z) for |z| > 2 is
Answer: B, No solution
Actual answer is:
[-1.33 -5]
[-2 -4]
the answer is a add -19w and dont forget to do it on each side
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
