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tangare [24]
2 years ago
10

Q, Fixed a system of coordinates in the plane, conficer the curve C having equation y = (x-2)^2. The line x + y - 2 = 0 intersec

ts C in:
(A)1 poin

(B) no point

(C) 2 points

(D) infinitely many points

3 points
Mathematics
2 answers:
Liula [17]2 years ago
5 0

Answer:

C

Step-by-step explanation:

y = (x - 2)² = x² - 4x + 4 → (1)

x + y - 2 = 0 → (2)

substitute y = x² - 4x + 4 into (2)

x + x² - 4x + 4 - 2 = 0

x² - 3x + 2 = 0

(x - 1)(x - 2) = 0

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

substitute these values into (2) and solve for y

x = 1 : 1 + y - 2 = 0 ⇒ y - 1 = 0 ⇒ y = 1 ⇒ (1, 1 )

x = 2 : 2 + y - 2 = 0 ⇒ y + 0 = 0 ⇒ y = 0 ⇒ (2, 0 )

the line intersects curve C at 2 points (1, 1 ) and (2, 0 )

Ludmilka [50]2 years ago
3 0

Answer:

Step-by-step explanation:

ok

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Finger [1]

Answer:

Exact Form:

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Decimal Form:

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Mixed Number Form:

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Substitute the value of the variable into the equation and simplify.

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If it was the first two, it would be to small of an angle.

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3 years ago
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Find the range for the function: y=x-7 {-3,0,2,5}
trasher [3.6K]

Answer:

Range is : { -10, -7, -5, -2 }

Step-by-step explanation:

Given:

The function is given as:

y=x-7

The domain of the function = { -3, 0, 2, 5 }

A function's input is called its domain and a function's output is called its range.

The range depends on the domain values. So, the values of 'y' are the values of range and the values of 'x' are the values of domain.

Here, the domain is given as:

Domain = { -3, 0, 2, 5 }

We need to find the values of 'y' for each value of 'x' taken from the domain set.

Plug in x=-3. This gives,

y=-3-7=-10

Plug in x=0. This gives,

y=0-7=-7

Plug in x=2. This gives,

y=2-7=-5

Plug in x=-5. This gives,

y=5-7=-2

Therefore, the set of all values of 'y' is the range.

Range is equal to { -10, -7, -5, -2 }.

8 0
4 years ago
Which is the polynomial function of lowest degree with rational real coefficients, a leading coefficient of 3 and roots StartRoo
anastassius [24]

Answer:

a) f(x)=3x^{3}-6x^{2}-15x+30

Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

x_{1}=\sqrt{5}\:x_{2}=2

2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form x'=\sqrt{a}+b  then its conjugate x''=\sqrt{a}-b. is also a root of this polynomial.

Therefore

x_3=-\sqrt{5}

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30

4 0
3 years ago
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