Question

On the moon, the acceleration due to gravity is -1.6 meters per second per second. A stone is dropped from a cliff on the moon and hits the surface of the moon 20 seconds later.a) How far did it fall?b) What was its velocity at impact?

Answer 1

Answer:

How far did it fall? -320 meters

What was its velocity at impact? -32 m/s

Step-by-step explanation:

a) How far did it fall?

To calculate the distance traveled by the stone we must use the following formula:

$d=\frac{gt^{2}}{2}$

Sustituing the given values we have that:

$d=\frac{-1.6\times 20^{2}}{2}\\ d=\frac{-1.6\times 400}{2}\\ d=\frac{-640}{2}\\ d=-320 m$

The distance traveled by the stone was -320 meters under the released point

b) What was its velocity at impact?

To calculate the velocity we need to use the formula:

$v=gt$

Sustituing the given values we have that:

$v=(-1.6)(20)\\v=-32 m/s$

So the velocity is -32 meteres per second, the negative sign indicate that the object is going down