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Marysya12 [62]
3 years ago
11

Which description is paired with its correct expression? two less than the quotient of a number cubed and four, increased by eig

ht; 2 minus StartFraction n cubed Over 4 EndFraction + 8 six times the difference of five and a number squared; 6 (n squared minus 5) three more than the quotient of nine and a number cubed, decreased by two; 3 + StartFraction 9 Over n cubed EndFraction minus 2 twice the difference of a number squared and three; 2 n squared minus 3
Mathematics
2 answers:
Annette [7]3 years ago
5 0

Answer:

Three more than the quotient of nine and a number cubed, decreased by two; 3 + StartFraction 9 Over n cubed EndFraction minus 2

Step-by-step explanation:

Nady [450]3 years ago
5 0

Answer:

C

Step-by-step explanation:

i took the review

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Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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