Answer:
B,,,,,,,,, 2, 6, 10, and -8
Step-by-step explanation:
Coefficients are any numbers part of an equation
Answer;
they are both closer to 0
Step-by-step explanation:
9/9= 1
4/9= approximately 0.5
8/8= 1
4/8= 0.5
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
86
Step-by-step explanation:
![48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2{1 (2 - 15÷3)}] \\ 8[ - 2.5{ (2 - 15÷3)}] \\ 8[ - 2.5{ ( - 13÷3)}] \\ 8[ - 2.5{ ( - 4.3)}] \\ 8[10.75 { }] \\ = 86](https://tex.z-dn.net/?f=48%C3%B76%20%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%7B1%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20-%2013%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20%20-%204.3%29%7D%5D%20%5C%5C%208%5B10.75%20%7B%20%7D%5D%20%5C%5C%20%20%3D%2086)
