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Mekhanik [1.2K]
3 years ago
13

Consider the original triangle and the reduction. What is the length of side A in centimeters?

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0
The answer is 6 since the scale factor is 2 and 3x2 is 6
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Let f and g be functions. (a) The function (f + g)(x) is defined for all values of x that are in the domain(s) of ____________.
krok68 [10]

Answer:

a) for all values of x that are in the domains of f and g.

b) for all values of x that are in the domains of f and g.

c) for all values of x that are in the domains of f and g with g(x)≠0

Step-by-step explanation:

a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.

b) By definition (fg)(x)=f(x)g(x).  Then x must be in the domain of f and g.

c) By definition (f/g)(x)=f(x)/g(x).  Then x must be in the domain of f and g and g(x) must be different of 0.

5 0
3 years ago
11. What's the perimeter of a regular heptagon if one side measures 3 inches?
NemiM [27]
When a polygon is regular, that means that all of its sides are the same length and all of its angles are the same. A heptagon has seven sides and you know that all of them measure 3 inches. You can find the perimeter by adding all of the side measures together, so 3 + 3 + 3 + 3 + 3 + 3 + 3, or 3 x 7. So, the perimeter of the heptagon is 21 inches.
7 0
3 years ago
Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of \over{AB}.

Step-by-step explanation:

To construct a perpendicular for \over{AB}, we must first take a compass & take the distance of its arms wider than half the length of \over{AB}.

This is done in order to get two intersecting arcs in the top & bottom of \over{AB} so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above \over{AB}, draw a line joining these 2 points through their points of intersection. The point where it intersects \over{AB} is the middle-most point of \over{AB} & now a perpendicular bisector of \over{AB} is constructed.

\rule{150pt}{2pt}

3 0
2 years ago
Enter an inequality that represents the graph in the box.
ANTONII [103]

The inequality that represents the graph in the box  is

y>-3x+6

Given :

The graph of the linear inequality

Lets pick two points from the graph to frame the linear equation

Slope intercept form of the equation is

y=mx+b

Where m is the slope and b is the y intercept

y intercept is (0,6) from the graph

so b=6

Now we find out slope m  using formula

Pick two points (0,6) and (2,0)

slope = \frac{y_2-y_1}{x_2-x_1} \\m=\frac{0-6}{2-0} =-3

m=-3

So the equation is y=-3x+6

Now we check the inequality sign by testing any point on shaded area

lets pick (4,0)

lets plug in 4 for x  and 0 for y

y=-3x+6\\0=-3(4)+6\\\\0=-6\\0>-6

The inequality for the given graph is

y>-3x+6

we cannot use >= sign because we have dotted lines

Learn more : brainly.com/question/17203372

5 0
3 years ago
PLEASE HELP ME BY ANSWERING AT LEAST 2 QUESTIONS MY WORK IS DUE IN LESS THAN AN HOUR!
levacccp [35]

nononononon nonononononno

Step-by-step explanation:

nonononononomonjknonkkom

8 0
3 years ago
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