Answer:
I think the answer is 672 please be right
To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"
Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.
Now, we have to recall that:
- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles
- also the sum of all the angles in any triangle is 180 degrees
Now, considering the isosceles triangle OQR, we have that:

Now, since the figure already shows that angle
Now, since we have established that the base angles
we can now solve the above equation for m<2 as follows:

Therefore, the correct answer is: option D
Coming from a 6th grader but I hope this is right!
Polynomials of degree greater than 2 can have more than one max or min value. The largest possible number of minimum or maximum points is one less than the degree of the polynomial. The following examples illustrate several possibilities.
since the degree is 4
number of possible extreme values = 4 -1 = 3
Find Angle B: B = 180 - (82+55) = 43. Then apply the law of sines:
b 8 cm
--------- = ----------
sin 43 sin 55
(sin 43)(8 cm)
Solving for b, we get b = ------------------- = 6.66, or 6.7 (cm, to the nearest tenth).
sin 55