PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
X = 4/7 = 0.571 I believe so
d = Diameter of wheels = 25 inches
s = Distance to be traveled by the wheels = 458 miles
Converting the miles to inches

The distance traveled by the wheels in rotation is the circumference

The number of rotations required to cover the distance would be

rotation is
so

The number of rotations to cover the required distance is 
Learn more:
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Answer: 19º
Step-by-step explanation:
Use sine

