11th term is 10240
Step-by-step explanation:
- Step 1: Given the sequence 10,20,40. So a(1) = 10, common ration, r = 20/10 = 2 Find the 11th term using the nth term formula, a(n) = ar^n-1
⇒ a(11) = 10 × 2^10 = 10 × 1024 = 10240
The width is 9.982 cm and the area is 34.07 and the diagonal is 9.52 I have I answered what you’re asking.
The <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>
<em>Recall:</em>
- Based on the Side-Side-Side Congruence Theorem, (SSS), two triangles can be said to be congruent to each other if they have three pairs of congruent sides.
Thus, in the two triangles given, the two triangles has:
- Two pairs of congruent sides - HI ≅ ML and IJ ≅ MN
Therefore, an <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>
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Learn more about SSS Congruence Theorem on:
brainly.com/question/4280133
Answer:
286.97
Step-by-step explanation:
find the area of the rectangle first
14*15=210
Next
Find the area of a circle
πr^2=a
the radius of the circle is half the height of the rectangle
π*(7*7)=a
a=153.94
Now
Divide the area by two
153.94/2=76.97
Now add the two areas
76.97+210
Answer:
AD also equal 14
Step-by-step explanation:
