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KiRa [710]
2 years ago
11

If the circumference of the circle below is 90, what is the length of the minor arc)? 609 A. 90 B. 15 C. 30 D. 10

Mathematics
1 answer:
Mazyrski [523]2 years ago
4 0

Answer:

arc XY = 15 units

Step-by-step explanation:

<u>GIVEN :-</u>

  • Angle subtended by arc XY at center = 60°
  • Circumference of the circle = 90 units.

<u>TO FIND :-</u>

  • Length of XY

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

Length of arc of the sector = \frac{\theta}{360} \times (Circumference \: of \: the \: circle) where θ is the angle subtended by arc of the sector at the center of the circle.

<u>SOLUTION :-</u>

XY = \frac{60}{360} \times 90 = \frac{90}{6} = 15

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A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. In earlier stu
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Answer:

75

Step-by-step explanation:

6 0
3 years ago
2 1/4 x2 1/4 in mixed number
maks197457 [2]

Answer:

5 \frac{1}{16} is the answer.

Step-by-step explanation:

Given:

2 \frac{1}{4} \times 2 \frac{1}{4}

<u>Step 1: Converting the mixed fraction into  fraction:</u>

Multiply  4 by 2 add  1 to the result.

<u></u>2\frac{1}{4}  =  \frac{4 \times 2+1}{4}

=\frac{8+1}{4}

=\frac{9}{4}

<u>Step 2: Performing the multiplication using the fraction</u>

= >\frac{9}{4} \times \frac{9}{4}

=> \frac{81}{16}

<u>Step 3: Converting the product back to  mixed fraction </u>

divide 81 by 16 and find the remainder

=>quotient \frac{remainder}{divisor}

Dividing 81 by 16 we get  5 as quotient and 1 as remainder

Thus the result in  mixed fraction will be

=> 5 \frac{1}{16}

4 0
3 years ago
70
BaLLatris [955]

Answer:

160 is the answer please tell me if im wrong

5 0
2 years ago
Find the distance between points having coordinates -10 and 5
Genrish500 [490]
The distance is 15 because -10 + 15 = 5
6 0
3 years ago
Part A: Solve −np − 70 &lt; 40 for n. Show your work. (4 points) Part B: Solve 4w − 7k = 28 for k. Show your work.
kondaur [170]
Hey!

For part A, let's write the problem,
-np-70\ \textless \ 40
Add 70 to both sides...
-np-70+70\ \textless \ 40+70
-np\ \textless \ 110
We are going to reverse the inequality, to do this we are going to multiply both sides by -1.
\left(-np\right)\left(-1\right)\ \textgreater \ 110\left(-1\right)
pn\ \textgreater \ -110
Divide both sides by p.
\frac{pn}{p}\ \textgreater \ \frac{-110}{p}
Our answer would be,
n\ \textgreater \ -\frac{110}{p}

Let's go with Part B. Let's write the problem,
4w-7k=28
Subtract 4w from both sides,
4w-7k-4w=28-4w
-7k=28-4w
Divide both sides by -7.
\frac{-7k}{-7}=\frac{28}{-7}-\frac{4w}{-7}
If we simplified it, we would be left with,
k=-\frac{28-4w}{7}

Thanks!
-TetraFish

4 0
3 years ago
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