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KiRa [710]
2 years ago
11

If the circumference of the circle below is 90, what is the length of the minor arc)? 609 A. 90 B. 15 C. 30 D. 10

Mathematics
1 answer:
Mazyrski [523]2 years ago
4 0

Answer:

arc XY = 15 units

Step-by-step explanation:

<u>GIVEN :-</u>

  • Angle subtended by arc XY at center = 60°
  • Circumference of the circle = 90 units.

<u>TO FIND :-</u>

  • Length of XY

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

Length of arc of the sector = \frac{\theta}{360} \times (Circumference \: of \: the \: circle) where θ is the angle subtended by arc of the sector at the center of the circle.

<u>SOLUTION :-</u>

XY = \frac{60}{360} \times 90 = \frac{90}{6} = 15

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Answer:

178

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Step-by-step explanation:

Sasha= 5 times Bess and Jeremy

1900 = 5 (202 + X)

/5             /5

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8 0
3 years ago
Martha Washington walks 30 minutes each day. If she walks for 140 days, how many hours will she walk?
telo118 [61]

70

make 30 minutes into an hour then divide 140 by 2

140/2=70

70x1=70

5 0
2 years ago
A woman is looking for a biker square office. She finds at office twice the area of her current office. If the perimeter of her
MatroZZZ [7]

Answer:

968

Step-by-step explanation:

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22 * 22 = 484

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8 0
3 years ago
Read 2 more answers
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
The angle of the elevation from the top of a 95 Todd building into a hot air balloon in the sky and 76° if the horizontal distan
AnnZ [28]

Answer:

The height of the hot air balloon is 1514.54 feet approximately.

Step-by-step explanation:

Consider the provided information.

The angle of elevation from the top of a 95-foot tall building to a hot air balloon in the sky is 76. If the horizontal distance between the building and the hot air balloon is 354 feet, find the height of the hot air balloon

The figure is shown below:

Let the height of the balloon is AD, the height of the building is BC.

Draw a line BE parallel to CD.

Therefore, AD=x+95, BC=95 and BE=CD=354 ft

Now in triangle ABE.

\tan\theta=\dfrac{\text{Opp}}{\text{Adj}}

\tan76^{\circ}=\dfrac{AE}{BE}

AE\approx 4.01\times 354

AE\approx 1419.54

The height air balloon is 1419.54+95 =1514.54 ft

Hence, the height of the hot air balloon is 1514.54 feet approximately.

7 0
3 years ago
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