Answer:
The answer is C.
Step-by-step explanation:
Given that (5,k) lies on the line that has the equation of 2x + y = 9. So in order to find k, you have to substitute the coordinates into the equation :
![2x + y = 9](https://tex.z-dn.net/?f=2x%20%2B%20y%20%3D%209)
Let x = 5,
Let y = k,
![2(5) + k = 9](https://tex.z-dn.net/?f=2%285%29%20%2B%20k%20%3D%209)
![10 + k = 9](https://tex.z-dn.net/?f=10%20%2B%20k%20%3D%209)
![k = 9 - 10](https://tex.z-dn.net/?f=k%20%3D%209%20-%2010)
![k = - 1](https://tex.z-dn.net/?f=k%20%3D%20%20-%201)
Answer:
Option (D) is correct
![(x-2)^{2} +(y+5)^{2} = 9](https://tex.z-dn.net/?f=%28x-2%29%5E%7B2%7D%20%2B%28y%2B5%29%5E%7B2%7D%20%3D%209)
Step-by-step explanation:
A circle has (a , b ) are the coordinates of the centre and
.
Given.
A circle is centered at (2,-5) and has radius 3
Let
and
and ![r=3](https://tex.z-dn.net/?f=r%3D3)
The standard form of the circle is.
------(1)
Put a, b and r value in equation 1.
![(x-2)^{2} +(y-(-5))^{2}= 3^{2}](https://tex.z-dn.net/?f=%28x-2%29%5E%7B2%7D%20%2B%28y-%28-5%29%29%5E%7B2%7D%3D%203%5E%7B2%7D)
![(x-2)^{2} +(y+5)^{2} = 9](https://tex.z-dn.net/?f=%28x-2%29%5E%7B2%7D%20%2B%28y%2B5%29%5E%7B2%7D%20%3D%209)
So. the standard form of equation is.
![(x-2)^{2} +(y+5)^{2}= 9](https://tex.z-dn.net/?f=%28x-2%29%5E%7B2%7D%20%2B%28y%2B5%29%5E%7B2%7D%3D%209)
Answer:me me aparece al revés
Step-by-step explanation:
Xd no entiendo =(