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marta [7]
4 years ago
12

The sum of two consecutive even integers is 82. What is the smaller number?

Mathematics
1 answer:
nata0808 [166]4 years ago
4 0
X=40
x+2=42
x+x+2=82
2x=80
x=40
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What is the solution to the inequality? -2/3(2x - 1/2) ≤ 1/5x - 1 Express your answer in interval notation.
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-\frac{2}{3}(2x-\frac{1}{2})\le \frac{1}{5}x-1


Multiply through by LCM of 15


(15) \times -\frac{2}{3}(2x-\frac{1}{2})\le 15(\frac{1}{5}x-1)





-10(2x-\frac{1}{2})\le 3x-15



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-20x+5\le 3x-15



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[\frac{20}{23}, \infty)







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3 years ago
If m+2/5 = 1/2, then which of the following is true?
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Leena consumes 400 cal at breakfast and 350 cal at lunch. She consumes 2/3 of her daily calories at dinner. If X represents the
Zina [86]
1) Data:

Meal                calories consumed

Breakfast          400 cal
Lunch               350 cal
Dinner                x
                       ------------------
Total                 400 + 350 + x = 750 + x

2) Equation: <span>

She consumes 2/3 of her daily calories at dinner => (2/3)[750+x] = x

3) Analyze each statement:

</span><span>a) Lena consumed 1500 cal at dinner.

Solve the equation to find if the statement is true:
</span>
<span><span>(2/3)[750+x] = x</span>

2(750+x) = 3x

1500 + 2x = 3x

1500 = 3x - 2x

x = 1500

Conclusión: TRUE stament.

b) Do you equation 2/3 (x+400+350)=x can be used to model the situation.

That is the same equation that I found above.

Conclusion: TRUE statement

c) Lena consumed 500 cal at dinner.

She consumed (2/3) * 1500 = 500 cal

Conclusion: TRUE statement

d) Lena consumed 1000 cal at dinner.

No, we calculated that she consumed 500 cal at dinner.

Conclusion: FALSE statement

e) The equation 2/3(x)=x(400+350) can be used to model the situation.

No: (2/3) x = 500 and x(400+350) = 500*750 = 375,00, which are not equal.

Conclusion: FALSE statement.

f) The equation 2/3x(400+350)=x Can’t be used to model the situation

No: in that equation the variable x cancels out because it appears a factor at both sides.

</span>Conclusion: TRUE statement
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4 years ago
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