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anzhelika [568]

3 years ago

15

Given that the federal and state biweekly deductions for a single person making $1,300 with zero withholding allowances working

in New York are $174 and $54.70 respectively, determine the net biweekly income.
a.
$1053.08
c.
$1071.30
b.
$1067.11
d.
$1079.13

2 answers:

katrin2010 [14]3 years ago

4 0

Answer:

C). $1071.30

Step-by-step explanation:

edge2021

Ainat [17]3 years ago

3 0

Answer:

ya

Step-by-step explanation:

it is d.

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Mr. Brown's salary is $32,000 and it increases by 3% each year. What is the explicit rule for this sequence in simplified form?

katovenus [111]

Answer:

This is the concept of geometric series. We are required to find the recursive formula for year n. Here we will use the formula;

nth=ar^(n-1)

where;

a=first term

r=common ratio

n=nth term

Thus

a=8.50

r=(8.85)/(8.50)=1.0412

thus the formula will be:

nth=8.50(1.0412)^n

3 0

3 years ago

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the

Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be $x.$

And the hotel charge in second city before tax be $y.$

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

$y=x-1500$ ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of $x$ + 10% of $y$ = $670.

$\frac{6x}{100} +\frac{10y}{100} =670$

$0.06x+0.10y=670$

Substituting the value of $y$ from equation (1) we get:

$0.06x+0.10(x-1500)=670$

$0.06x+0.10x-150=670$

$0.16x-150=670$

<em>Adding both sides by 150 we get:</em>

$0.16x=820$

<em>Dividing both sides by 0.16 we get:</em>

$x=5125.$

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of $x$ in equation (1) we get:

$y=x-1500$

$y=5125-1500$

$y=3625.$

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0

3 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago

The value of y varies directly with x and y 8 when x 2 find y when x 10 answer

Zielflug [23.3K]

8:2=4:1 Answer y=40
hope this helps.

4 0

3 years ago

About 543 out of every 1,000 people in United States owned a cell phone in 2003.In japan,the are was 68 for every 100 people.How

Softa [21]

Answer:

The greater percent of cell phone ownership in Japan than the U.S was <u>13.7%</u>.

Step-by-step explanation:

Given:

About 543 out of every 1,000 people in United States owned a cell phone in 2003.

In japan,the are was 68 for every 100 people.

Now, to find the greater percent of cell phone ownership in Japan than the U.S.

So, to get the percent of people owned cell phone in United States:

$\frac{543}{1000}\times 100$

$=0.543\times 100$

$=54.3\%.$

Now, to get the percent of people owned cell phone in Japan:

$\frac{68}{100} \times 100\\\\=0.68\times 100\\\\=68\%.$

So, to get the percent greater of cell phone ownership in Japan than the U.S we subtract the percent of people owned cell phone in United States from the percent of people owned cell phone in Japan:

$68\%-54.3\%\\\\=13.7\%.$

Therefore, the greater percent of cell phone ownership in Japan than the U.S was 13.7%.

5 0

3 years ago