Check the picture below.
well, we know the triangle is an isosceles, so it has twin sides coming from the "vertex" down to the "base", running an angle bisector from the "vertex" will give us a perpendicular to the "base", let's find its height.
![\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=\stackrel{adjacent}{5}\\ b=\stackrel{opposite}{h}\\ \end{cases} \\\\\\ \sqrt{13^2 - 5^2}=h\implies 12=h](https://tex.z-dn.net/?f=%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Csqrt%7Bc%5E2%20-%20a%5E2%7D%3Db%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7B13%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B5%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7Bh%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Csqrt%7B13%5E2%20-%205%5E2%7D%3Dh%5Cimplies%2012%3Dh)
so we simply need to get the area of a triangle whose base is 10 and height is 12.
![A=\cfrac{1}{2}(\underset{b}{10})(\underset{h}{12})\implies \boxed{A=60}](https://tex.z-dn.net/?f=A%3D%5Ccfrac%7B1%7D%7B2%7D%28%5Cunderset%7Bb%7D%7B10%7D%29%28%5Cunderset%7Bh%7D%7B12%7D%29%5Cimplies%20%5Cboxed%7BA%3D60%7D)
Answer: B. No
Step-by-step explanation: Let's think of the variable x as apples. If there are 7 apples and then you added 1 other something, that would be different than having 1 apple and adding 7 other somethings. The equations would have a different amount of somethings and apples.
x=49
please,mark as, brainliest
Step-by-step explanation:
(-3,-2) is the answer friend.....
Answer:
-66
Step-by-step explanation:
-4n+6
-72+6
-66
might not be right thk