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3 years ago

8

Draw the following graph on the interval −195∘ : y=cos(x)+2 What is the amplitude of the function? What is the perio

d of the function?

1 answer:

Darya [45]3 years ago

6 0

y=cos(x)+2

What is the amplitude of the function?

What is the period of the function?

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Find the value of x, rounded to the nearest tenth. Answers : a.)12.5 b.)9.7 c.) 10.0 d.) 13.0

Anuta_ua [19.1K]

Remember "SOH CAH TOA"

Sine = (Opposite/Hypotenuse)

Cosine = (Adjacent/Hypotenuse)

Tangent = (Opposite/Adjacent)

In this case, we will be using cosine, and our equation will be $\frac{cos(28)}{1} =\frac{11}{x}$

So firstly, cross-multiply. $cos(28)*x=11$

Next, divide both sides by cos(28), and your answer will be $x=12.5$

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A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. Which of the following proportions could you use to d

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3 years ago

Rowan has $60. He wants to leave a 20% tip on his restaurant bill. His restaurant bill is $52.22.

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Answer:

Step-by-step explanation:

20% tip on 52.22 is 10.44

52.22*0.2=10.44

I don't think he has enough to do it though

52.22+10.44=62.664

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2 years ago

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3 years ago

Which of the following equations is in equation formed when completing the square on y^2 - 12 y= -27

bogdanovich [222]

Answer:

$(y-6)^2=9$

Step-by-step explanation:

Given

$y^2 - 12y = -27$

Required

Get equivalent expression using completing the square

<em>Follow these steps:</em>

<em>Take the coefficient of y; That is -12</em>

<em>Divide it by 2; That is (-12/2)</em>

<em>Square it: (-12/2)^2</em>

<em />

Add to both sides of the equation

$y^2 - 12y + (\frac{-12}{2})^2= -27 + (\frac{-12}{2})^2$

$y^2 - 12y + (-6)^2= -27 + (-6)^2$

$y^2 - 12y + 36= -27 + 36$

$y^2 - 12y + 36= 9$

Expand the right-hand side

$y^2 - 6y - 6y + 36= 9$

Factorize:

$y(y-6)-6(y-6) =9$

$(y-6)(y-6)=9$

$(y-6)^2=9$

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3 years ago