Question

Solve the system of linear equations in two variables by elimination or substitution.

Answer 1

Answer:

( $\frac{1}{2}$, 0 )

Step-by-step explanation:

Given the 2 equations

4x + 3y = 2 → (1)

2x - 3y = 1 → (2)

Adding (1) and (2) term by term will eliminate the y- term, that is

6x = 3 ( divide both sides by 6 )

x = $\frac{3}{6}$ = $\frac{1}{2}$

Substitute x = $\frac{1}{2}$ into either of the 2 equations and evaluate for y

Substituting into (1)

4($\frac{1}{2}$ ) + 3y = 2

2 + 3y = 2 ( subtract 2 from both sides )

3y = 0 ⇒ y = 0

Solution is ( $\frac{1}{2}$, 0 )