Please help with both of them please
1 answer:
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Answer:
(x + 7)^2 + (y + 1)^2 = 25.
Step-by-step explanation:
The center of a circle is easy to set up. According to the formula below, the formula for the circle will be (x - a)^2 + (y - b)^2 = r^2.
In this case, a = -7 and b = -1, so we have...
(x - (-7))^2 + (y - (-1))^2 = r^2
(x + 7)^2 + (y + 1)^2 = r^2
To get the radius, we need to find the distance between the center and the point on the circle. The distance formula is d = sqrt((x2 - x1)^2 + (y2 - y1)^2).
In this case, x2 = -4, x1 = -7, y2 = 3, and y1 = -1.
sqrt((-4 - -7)^2 + (3 - -1)^2) = sqrt((-4 + 7)^2 + (3 + 1)^2) = sqrt((3)^2 + (4)^2) = sqrt(9 + 16) = sqrt(25) = plus or minus 5.
Since distance can only be positive, the distance is 5 units, meaning that the radius is 5 units.
5^2 = 25
So, your equation should be (x + 7)^2 + (y + 1)^2 = 25.
Hope this helps!
Step-by-step explanation:
We have given,
A rational function : f(x) =
W need to find :
Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.
For no values of x, we get indetermined form (i.e ), Hence there is no holes
Vertical Asymptotes:
Plug y=f(x) = ∞ in f(x) to get vertical asymptote {We can us writing ∞ = }
i.e ∞ =
or
or x-4 =0
or x=4, Hence at x = 4, f(x) has a vertical asymptote
X -intercept :
Plug f(x)=0 , to get x intercept.
i.e 0 =
or x - 2 =0
or x = 2
Hence at x=2, f(x) has an x intercept
Horizontal asymptote:
Plug x = ∞ in f(x) to get horizontal asymptote.
i.e f(x) = =
or f(x) =
or f(x) = 1 = y
hence at y =f(x) = 1, we get horizontal asymptote