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2 answers:
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Answer:
D. I and III only
Step-by-step explanation:
Number of first fie defects are given as 9,7,10,4 and 6.
First we have to arrange the above data in ascending order which is 4,6,7,9,10
- Now if we consider the defect in sixth car to be 3 then our data will look like: 3,4,6,7,9,10
So the mean of above data would be = 6.5
and Median of the above data would be = =
= 6.5
Hence mean and median number of defects are same if the sixth car has 3 defects.
- Now if we consider the defect in sixth car to be 12 then our data will look like: 4,6,7,9,10,12
So the mean of above data would be = 8
and Median of the above data would be = =
= 8
Hence mean and median number of defects are same if the sixth car has 12 defects.
- But Now if we consider the defect in sixth car to be 7 then our data will look like: 4,6,7,7,9,10
So the mean of above data would be = 7.167
and Median of the above data would be = = 7
Hence mean and median number of defects are not same if the sixth car has 7 defects.
Therefore option D is correct.
Answer:
From the attached graphic, we can see:
(SP + PR) * PR = (WQ + QR) * QR
SP * PR + PR^2 = WQ * QR + QR^2
4 SP + 4*4 = 8 * 5 + 25
4 SP + 16 = 65
4 SP = 49
SP = 49 / 4
SP = 12.25
Step-by-step explanation:
