What steps would you follow in order to solve the equation?
1 answer:
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The easiest way to solve this is to divide the shape into 2 rectangles.
The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5
So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)
And for the smaller one it is a little bit trickier.
So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle
At the top we see that it says 6ft
We can do 10-6 to find the missing measurement.
Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10
So 10-6 = 4
Which means the number we need is 4
So now we have 5 x 4 = 20
72 + 20 = 92
Answer: 92
I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!
The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5
So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)
And for the smaller one it is a little bit trickier.
So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle
At the top we see that it says 6ft
We can do 10-6 to find the missing measurement.
Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10
So 10-6 = 4
Which means the number we need is 4
So now we have 5 x 4 = 20
72 + 20 = 92
Answer: 92
I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!
Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,