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HACTEHA [7]
3 years ago
13

Y = x2 – 3x + 2use the discriminant to determine the number of solutions​

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

2 real solutions

Step-by-step explanation:

The formula for determining the discriminant is b² - 4ac.

So, let's identify our variables.

a = 1

b = 3

c = 2

Now, we can plug in our values.

3² - 4(1)(2)

9 - 8

1

1 is the discriminant of this function, and since 1 is positive, this indicates that there are two distinct real number solutions.

anygoal [31]3 years ago
6 0
Mj3mar gave the answer thanks to him I wouldn’t have got my question right
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25. An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this
Viktor [21]

Answer:

a. 144 ft

b. 5 s

Step-by-step explanation:

h = -16t² + 64t + 80

a. This is a parabola, so the maximum height is at the vertex.

t = -64 / (2 × -16)

t = 2

h = -16(2)² + 64(2) + 80

h = 144

The apple reaches a maximum height of 144 ft.

b. 0 = -16t² + 64t + 80

0 = t² − 4t − 5

0 = (t + 1) (t − 5)

t = -1 or 5

t must be positive, so it takes 5 seconds to reach the ground.

3 0
3 years ago
HELP PLEASE!!! WILL GIVE BRAINLIEST
Nadusha1986 [10]
The equation looks like this \frac{ x^{2} }{16} + \frac{ y^{2} }{25} =1.  In an ellipse, a is always the bigger value, so a^2 = 25.  This bigger value also tells us which axis is the major one.  Sine the bigger value a is under the y^2 of the equation, the major axis is the y-axis.  This is a vertical ellipse.  The center is always found within a set of parenthesis that exist with the x^2 and the y^2.  Since there are no parenthesis with either, there is no side to side movement, nor is there any up or down movement.  So the center doesn't move from the origin (0, 0).  The vertex is also along the major axis, and if a^2 is 25, then a = 5, so the vertices go up 5 from the center and down 5 from the center.  Vertices are (0, 5) and (0, -5).  The foci follow the formula c^{2}= a^{2}- b^{2}.  c is the distance that the foci are from the center.  c^{2}=25-16 and c = 3.  The foci also lie on the major axis, so the coordinates for the foci are (0, 3) and (0, -3).  There you go!
8 0
3 years ago
In a scale drawing, a building has a length of 15 cm. The actual length of the building is 37.5 feet. Whats the scale of the dra
Feliz [49]

Answer:

\frac{15}{37.5}\ \frac{cm}{ft}

or

1.31:100

Step-by-step explanation:

we know that

The scale of the drawing is equal to divide the length of a building in the scale drawing by the actual length of a building

so

\frac{15}{37.5}\ \frac{cm}{ft}

That means

15 cm in the drawing represent 37.5 ft in the actual

Remember that

1\ ft=30.48\ cm

Convert 15 cm to ft

divide by 30.48

15\ cm=15/30.48\ ft

substitute

\frac{15}{37.5}\ \frac{cm}{ft}=\frac{(15/30.48)}{37.5}=\frac{0.0131}{1}

or

1.31:100

That means

1.31 units in the drawing represent 100 units in the actual

5 0
3 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
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Maksim231197 [3]
The correct answer is A Marie does not know how many cherries she has to share. She knows she is sharing her cherries equally with 3 friends
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