Answer: BC = 54 <kjm=44
Step-by-step explanation:
1st 0ne-
if you look at it as 2 triangles with D being the shared side- I can determine that the angles are congruent (by SSA theorem)
so
6x=9x-27 (by corresponding parts of congruent Theorem)
-3x=-27
x=9
BC- 9(9)-27= 81-27=54
2nd one-
J bisects KJM
4x+6=3x+10
x=4
3(4)+10= 22
4(4)+6= 22
KJM= 22+22= 44
Answer:
Slope is -2
Step-by-step explanation:
(y2-y1) / (x2-x1)
(6-10) / (-10+12) = (-4)/(2) = <u>-2</u>
Answer:
5cm
Step-by-step explanation:
Find the diagram attached.
From ΔBCD, ∠BCD = 90-∠ACD
∠BCD = 90-60
∠BCD = 30°
Also tan60 = CD/BD
tan 60 = CD/5
CD = 5tan60
CD = 5√3 cm
Similarly from ΔACD, tan30 = CD/AD
tan30 = 5√3/AD
AD = 5√3/tan30
AD = 5√3/(1/√3)
AD = 5√3 * √3/1
AD = 5 cm
Hence the length of side AD is 5cm
-4n+4n=0
First you would combine like terms
so if you add -4n and 4n together you get 0
and 0=0
so the answer is infintely many solutions
(x²+4x+3)/2(x²-10x+25)
the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5
the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5
this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)] for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
