Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
F= -3/5 x+2. Hope this helps
The correct answer is: "
" .
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<u>Step-by-step explanation</u>:
Based on the assumption that the "1" repeats infinitely; in the given value:
" 33.61111111 ...." ;
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Note that the "611" ; after the decimal point; this goes to the "thousandths";
place (is "3 (three) digits long.").
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As such; we rewrite the number as:
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"
" ;
and we multiply BOTH the "numerator" And the "denominator" by: "1000" :
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→ "
" ;
to get:
→ "
" ; → which cannot be reduced any further.
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The correct answer is: "
" .
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Hope this is helpful to you!
Wishing you the best!
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Answer:
<em>Circumference:</em> 18.84 cm
<em>Area:</em> 28.26 cm^2 (exponent 2)
Step-by-step explanation:
Circumference = 2(pi)r
The diameter is 6. Means the radius is 3 (half of 6)
pi = 3.14
2(3.14) x 3 = 18.84
Circumference is 18.84 cm.
Area of a circle = (pi)r^2
(3.14)(3)^2 = 28.26 cm^2 (exponent 2)