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Nata [24]
3 years ago
9

PLEASE HELP ME pleasee!

Mathematics
1 answer:
kap26 [50]3 years ago
4 0

Answer:

b 2

Step-by-step explanation:

x is an integer that is greater than 3 and less than or equal to 6.

x can be 4, 5, 6.

Answer: b 2

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I NEED HELP!!! NOW!!!! A shape is picked at random from the group below.
evablogger [386]

Answer:

not picking a circle, not picking a square, and picking a shape that has only straight edges.

Step-by-step explanation:

All of these are 6/8, or 3/4.

7 0
4 years ago
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Please help. I'm not the best at math.
Elena L [17]
5:4 Should be correct! I took the test Btw Hope this helps!! :D

5 0
3 years ago
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Simplify the expression 11+2/3(15-21a)
Delvig [45]

Answer:

21-14a

Step-by-step explanation:

You have to distribute the (2/3) into the (15-21a) then add it to the 11.  So after distributing the (2/3) into the (15-21a) is (10-14a).  Then add that to the 11

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3 years ago
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What is the range? The range is __
bearhunter [10]

Answer:

8

Step-by-step explanation:

Take the biggest value and smallest value, and subtract the smallest value from the biggest value:

9-1=8

3 0
2 years ago
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
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