Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Evaluate and reduce: 12 + (12) Enter the number that belongs in the green box. [?]

Firlakuza [10]

Answer:

24

Step-by-step explanation:

12 + (12)

first do for the bracket

12 + 12

24

3 0

3 years ago

Help please soon !!!!!!

stepan [7]

75.25x + 3604 = 300.50x
300.50x - 75.25x = 3604
225.25x = 3604
x = 16
Both companies charged the same at 16 tons
first answer 16 tons
--------------------
300.50x = 300.50(16) = $4,808
both companies charged the same are $4,808
second answer is $4,808

5 0

3 years ago

2. Addison bought 9 pumpkin pies for $27. How much will she pay for 11 pumpkin pies? Use numbers and words to explain your answe

Olin [163]

Answer:

$33

Step-by-step explanation:

Since 9 pies is 27 dollars that means you have to divide 27 by 9 to find out what 1 pie costs

1 pie ends cause costing $3

now you multiply the cost for 1 pie and 11 so it comes out to be $33

4 0

3 years ago

Read 2 more answers

In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen

Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type ni xi si

Graded 42 0.486 0.187

No-fines 42 0.359 0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

$Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}} + \frac{s_{2}^{2} }{n_{2}} } }$

$Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42} + \frac{0.02496 }{42} } }$

$Z = \frac{0.127 }{\sqrt{0.001468}}$

$Z = \frac{0.127 }{0.0377}$

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0

3 years ago

2 PART QUESTION!!

Llana [10]

Last answer for the first question and in not sure about the second one

4 0

3 years ago