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pshichka [43]
2 years ago
8

Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Mathematics
1 answer:
Fantom [35]2 years ago
3 0

Answer:

Step-by-step explanation:

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Can someone help with this geometry question?
Alex787 [66]

since it's rhombus, then

6x-11=25-4x

10x=36

x=3.6

each side = 25-4(3.6)

= 25 - 14.4

= 10.6

3 0
3 years ago
Read 2 more answers
I don’t know how to set it up nor do it please help me
marusya05 [52]

Answer:

The value of x is 3

Step-by-step explanation:

∵ Quadrilateral ABCD is congruent to quadrilateral JKLM

∴ AB = JK and BC = KL

∴ CD = LM and AD = JM

∵ BC = 8x + 7

∵ KL = 31

∵ BC = KL

→ Equate their right sides

∴ 8x + 7 = 31

→ Subtract 7 from both sides

∵ 8x + 7 - 7 = 31 - 7

∴ 8x = 24

→ Divide both sides by 8 to find x

∴ \frac{8x}{8} = \frac{24}{8}

∴ x = 3

∴ The value of x is 3

8 0
2 years ago
A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i
lutik1710 [3]

Answer: 1-(\frac{364}{365})^n

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^x, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

p=\dfrac{1}{365}

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

P(x\geq1)=1-P(x

Hence, the probability there is at least one day in a year when nobody has a birthday =1-(\frac{364}{365})^n

5 0
3 years ago
What is the product of the binomals below (2x+3) (3x+3)
Korvikt [17]

Answer:

3*(2x+3)*(x+1)

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

\left(2x+3\right)\left(3x+3\right)\\3x + 3  =   3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\

5 0
2 years ago
4x+(x-y/8)=17 and 2y+x-(5y+2/4)=2 by using elimination method
vladimir2022 [97]

Answer:

x=811/238, y=36/119. (811/238, 36/119).

Step-by-step explanation:

4x+(x-y/8)=17

2y+x-(5y+2/4)=2

-----------------------

4x+x-y/8=17

5x-y/8=17

40x-y=136

y=40x-136

------------------

2y+x-5y-2/4=2

2y-5y+x-1/2=2

-3y+x=2+1/2

-3y+x=4/2+1/2

-3y+x=5/2

-3(40x-136)+x=5/2

-120x+408+x=5/2

-119x=5/2-408

-119x=5/2-816/2

-119x=-811/2

119x=811/2

x=(811/2)/119

x=(811/2)(1/119)=811/238

y=40(811/238)-136

y=16220/119-136

y=36/119

x=811/238, y=36/119.

4 0
3 years ago
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