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3 years ago

What is the solution set for this linear-quadratic system of equations?

Mathematics

1 answer:

disa [49]3 years ago

5 0

I believe it is (5,8) , (-3,0) that's if you are solving for it

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Can we conclude that two similar figures can also be congruent figures? Explain.

shusha [124]

Answer:

In similar figures, the angles are congruent, even if the sides are not. Notice that one angle in each pair of figures corresponds to an angle in the other figure. They have the same shape but not the same size

7 0

3 years ago

Expand: In 2a3/b4 In 2 + 3 In a - 4 In b In 2 - 3 In a - 4 In b In 2-3 In a + 4 In b

weqwewe [10]

Answer:

ln(2) + 3ln(a) - 4ln (b)

Step-by-step explanation:

ln(2a^3 /b^4)

We know that ln(x/y) = ln (x) - ln y

ln(2a^3 ) - ln (b^4)

We know that ln (xy) = ln x + ln y

ln(2) + ln(a^3 ) - ln (b^4)

We know that ln(x^y) = y ln (x)

ln(2) + 3ln(a) - 4ln (b)

8 0

3 years ago

A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four

Firlakuza [10]

Answer:

The first four terms are 4,8,12,16

Step-by-Step Explanation:

The given relation between the nth term and it's previous term is given by:

$\boxed{an = an - 1 + 4}$

GiveN:

a1 = 4

Now finding the other three terms of the AP with the given relation.

$a2 = a1 + 4$

Putting a1 = 4,

$a2 = 4 + 4 = 8$

Now, Third term:

$a3 = a2 + 4$

Putting a2 = 8,

$a3 = 8 + 4 = 12$

Now, Fourth term:

$a4 = a3 + 4$

Putting a3 = 12,

$a4 = 12 + 4 = 16$

Hence, The first four terms of the AP is 4, 8, 12 & 16.

7 0

2 years ago

gladu [14]

Answer:

Hope this is correct

5 0

2 years ago

4/6, 7/12, 5/10

Elden [556K]

In order from least to greatest:
5/10 , 7/12 , 4/6
You have to find a common denominator of all 3 numbers which is 60 and then you proceed with the next steps.

7 0

3 years ago